Let's analyze the problem step-by-step: You want two numbers such that:
- When you multiply them, the result is a one-digit number (i.e., between 0 and 9).
- When you add them, the result is a two-digit number (i.e., between 10 and 99).
Step 1: Understand the constraints
- Multiplication result: 1 to 9 (assuming positive integers)
- Addition result: 10 to 99
Step 2: Try to find such pairs
Let's denote the two numbers as xxx and yyy.
- x×y≤9x\times y\leq 9x×y≤9
- x+y≥10x+y\geq 10x+y≥10
Step 3: Explore possibilities
Since the product is small (≤9), both numbers must be relatively small or one must be 1. Try some pairs:
-
(1, 9):
- Product: 1×9=91\times 9=91×9=9 (one-digit ✓)
- Sum: 1+9=101+9=101+9=10 (two-digit ✓)
This pair works!
-
(2, 5):
- Product: 2×5=102\times 5=102×5=10 (two-digit ✗)
No.
- Product: 2×5=102\times 5=102×5=10 (two-digit ✗)
-
(3, 4):
- Product: 3×4=123\times 4=123×4=12 (two-digit ✗)
No.
- Product: 3×4=123\times 4=123×4=12 (two-digit ✗)
-
(1, 8):
- Product: 1×8=81\times 8=81×8=8 (one-digit ✓)
- Sum: 1+8=91+8=91+8=9 (one-digit ✗)
No.
-
(1, 10):
- Product: 1×10=101\times 10=101×10=10 (two-digit ✗)
No.
- Product: 1×10=101\times 10=101×10=10 (two-digit ✗)
Conclusion:
The pair (1, 9) satisfies the condition perfectly:
- Multiply: 1×9=91\times 9=91×9=9 (one-digit number)
- Add: 1+9=101+9=101+9=10 (two-digit number)
If you want other pairs, you can try (1, any number between 9 and 98), but the
product will be larger than 9 once the second number is greater than 9, so
only (1, 9) works for positive integers. Answer:
The two numbers are 1 and 9.