starting from the point x, jayant walked 15 m towards west. he turned left and walked 20 m. he then turned left and walked 15 m. after this he turned to his right and walked 12 m. how far and in which directions is now jayant from x?

4 hours ago 6

It looks like some distances are missing in your query (the values for the first and third walks are not specified). To solve this problem accurately, I need the exact distances Jayant walked in each step. However, I can explain the method to find how far and in which direction Jayant is from the starting point xxx:

Step-by-step Method to Solve the Problem

Starting Point: Jayant starts at point xxx.
First Movement: Jayant walks m1m_1m1 meters towards the west.
Second Movement: He turns left (from west, turning left means facing south) and walks 20 meters.
Third Movement: He turns left again (from south, turning left means facing east) and walks m3m_3m3 meters.
Fourth Movement: He turns right (from east, turning right means facing south) and walks 12 meters.

How to find Jayant's final position relative to xxx:

Assign coordinates to the starting point xxx as (0, 0).
After first walk (west): position is (−m1,0)(-m_1,0)(−m1,0).
After second walk (south): position is (−m1,−20)(-m_1,-20)(−m1,−20).
After third walk (east): position is (−m1+m3,−20)(-m_1+m_3,-20)(−m1+m3,−20).
After fourth walk (south): position is (−m1+m3,−20−12)=(−m1+m3,−32)(-m_1+m_3,-20-12)=(-m_1+m_3,-32)(−m1+m3,−20−12)=(−m1+m3,−32).

Distance from xxx:

Use the distance formula:

d=(−m1+m3)2+(−32)2=(−m1+m3)2+1024d=\sqrt{(-m_1+m_3)^2+(-32)^2}=\sqrt{(-m_1+m_3)^2+1024}d=(−m1+m3)2+(−32)2=(−m1+m3)2+1024

Direction from xxx:

The x-coordinate is (−m1+m3)(-m_1+m_3)(−m1+m3).
The y-coordinate is −32-32−32.
If (−m1+m3)>0(-m_1+m_3)>0(−m1+m3)>0, Jayant is east of xxx; if < 0, west of xxx.
Since y-coordinate is negative, Jayant is south of xxx.