To find the output of the 3-input neuron with weights 1, 4, and 3, inputs 4, 8, and 5, and a linear transfer function with a constant of proportionality equal to 3, follow these steps:
- Calculate the weighted sum of the inputs:
(1×4)+(4×8)+(3×5)=4+32+15=51(1\times 4)+(4\times 8)+(3\times 5)=4+32+15=51(1×4)+(4×8)+(3×5)=4+32+15=51
- Multiply the weighted sum by the constant of proportionality (3):
Output=3×51=153\text{Output}=3\times 51=153Output=3×51=153
Therefore, the output of the neuron is 153